A set of numbers
forming a matrix N*N is passed as input. The program has to print the sum of
numbers along the diagonals.
Input
Format:
The first line
will contain the value of N. The next N lines will contain N numbers each
separated by one or more spaces.
Boundary
Conditions: 2 <= N <= 10 Value of a given number in the
matrix is from 0 to 99999999.
Output
Format:
The sum of the
numbers along the diagonals.
Example
Input/Output 1:
Input:
3
5 6 7
8 9 1
2 3 4
Output:
27
Explanation:
The sum of the
numbers along the diagonal = 5+9+4+7+2 = 27. Please pay attention in not
counting the overlapping number 9 (which is in the middle) twice.
Solution
1:
n=int(input())
a=[[int(i) for i
in input().split()]for i in range(n)]
x=sum(a[i][i]+a[i][n-1-i]
for i in range(n))
print(x) if n%2==0
else print(x-a[n//2][n//2])
Solution
2:
#include
<iostream>
using namespace
std;
int main()
{
int i,j,a,n,s=0;
cin>>n;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{
cin>>a;
if(i==j||i+j==n-1)
s+=a;
}
cout<<s;
}