A certain number of people attended a
meeting which was to begin at 10:00 am on a given day. The arrival time in
HH:MM format of those who attended the meeting is passed as the input in a
single line, with each arrival time by a space. The program must print the
count of people who came late (after 10:00 am) to the meeting.
Input
Format:
The first line contains the arrival time
separated by a space.
Output
Format:
The first line contains the count of late
comers.
Boundary
Conditions:
The length of the input string is between 4 to 10000. The time HH:MM will be in
24 hour format (HH is hours and MM is minutes).
Example
Input/Output 1:
Input:
10:00 9:55 10:02 9:45 11:00
Output:
2
Explanation:
The 2 people were those who came at 10:02
and 11:00
Solution
1:
#include<stdio.h>
int main()
{
int
x,y,s=0;
char c=' ';
while(c==' ')
{
scanf("%d:%d%c",&x,&y,&c);
if(x>10||x==10&&y>0)
s++;
}
printf("%d",s);
}
Solution
2:
#include <cstdio>
using namespace std;
int main()
{
int
x,y,s=0;
char c=' ';
while(c==' ')
{
scanf("%d:%d%c",&x,&y,&c);
if(x>10||x==10&&y>0)
s++;
}
printf("%d",s);
}
Solution
3:
s,c=[i.split(':') for i in
input().split()],0
for i in s:
if int(i[0])>10 or int(i[0])==10 and int(i[1])>0:
c+=1
print(c)