Toggle Alphabet Case

The program must accept an alphabet X and toggle the case (convert upper case to lower case and vice versa).

Input Format:

The first line denotes the value of character X.

Output Format:

The first line contains the characters X and the toggled case character separated by a hyphen.

Boundary Conditions: X is from a to z

Example Input/Output:

Input:

d

Output:

d-D

Solution:

s=input()

print(s+'-'+s.swapcase())

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Interlace odd-even from A to B

Two numbers A and B are passed as input. The program must print the odd numbers from A to B (inclusive of A and B) interlaced with the even numbers from B to A.

Input Format:

The first line denotes the value of A. The second line denotes the value of B.

Output Format:

The odd and even numbers interlaced, each separated by a space.

Boundary Conditions: 1 <= A <= 9999999 A < B <= 9999999

Example Input/Output 1:

Input:

5

11

Output:

5 10 7 8 9 6 11

Explanation:

The odd numbers from 5 to 11 are 5 7 9 11 The even numbers from 11 to 5 (that is in reverse direction) are 10 8 6 So these numbers are interlaced to produce 5 10 7 8 9 6 11

Solution:

#include <iostream>

using namespace std;

int main()

{

 int n,m,i,j;

 cin>>n>>m;

 for(i=n,j=m;i<=m;i++,j--)

  {

      if(i%2==1)

       cout<<i<<" ";

      if(j%2==0)

       cout<<j<<" ";

  }

}

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Print Calendar Month in Words

The program must accept an integer value N and print the corresponding calendar month in words. 1 - January, 2 - February, .... , 11 - November, 12 - December If any value apart from 1 to 12 is passed as input, the program must print "Invalid Input".

Input Format:

The first line denotes the value of N.

Output Format:

The first line contains the output as per the description. (The output is CASE SENSITIVE).

Boundary Conditions:

1 <= N <= 12

Example Input/Output 1:

Input:

5

Output:

May

Example Input/Output 2:

Input:

105

Output:

Invalid Input

Solution 1:

import calendar

n=int(input())

print(calendar.month_name[n]) if n<13 else print('Invalid Input')

Solution 2:

d={1:'January',2:'February',3:'March',4:'April',5:'May',6:'June',7:'July',8:'August',9:'September',10:'October',11:'November',12:'December'}

n=int(input())

print(d[n]) if n<13 else print('Invalid Input')

Solution 3:

#include<stdio.h>

int main()

{

int n;

scanf("%d",&n);

    switch(n)

    {

        case 1:

            printf("January");

            break;

        case 2:

            printf("February");

            break;

        case 3:

            printf("March");

            break;

        case 4:

            printf("April");

            break;

        case 5:

            printf("May");

            break;

        case 6:

            printf("June");

            break;

        case 7:

            printf("July");

            break;

        case 8:

            printf("August");

            break;

        case 9:

            printf("September");

            break;

        case 10:

            printf("October");

            break;

        case 11:

            printf("November");

            break;

        case 12:

            printf("December");

            break;

        default:

            printf("Invalid Input");

    }

}

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String Concatenation

Two string values S1 and S2 are passed as input. The program must print the output as S1 Technologies S2.

Input Format:

The first line denotes the value of S1. The second line denotes the value of S2.

Output Format:

The first line contains the output as per the description. There must be exactly one space between the words.

Boundary Conditions: Length of S1 is from 1 to 100. Length of S2 is from 1 to 100.

Example Input/Output 1:

Input:

Wipro

Bangalore

Output:

Wipro Technologies Bangalore

Solution:

x,y=input().strip(),input().strip()

print(x+' Technologies '+y)

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Perfect Number

Given a positive integer N as the input, the program must print yes if N is a perfect number. Else no must be printed.

Input Format:

The first line contains N.

Output Format:

The first line contains yes or no

Boundary Conditions: 1 <= N <= 999999

Example Input/Output 1:

Input:

6

Output:

yes

Example Input/Output 2:

Input:

8

Output:

no

Solution 1:

n,s,i=int(input()),1,2

while i*i<=n:

    if n%i==0:

        s+=i+n/i

    i+=1

print('yes') if n==s else print('no')

Solution 2:

#include <iostream>

using namespace std;

int main()

{

 int i,n,s=1;

 cin>>n;

 for(i=2;i*i<=n;i++)

  if(n%i==0)

   s+=i+n/i;

 s==n?cout<<"yes":cout<<"no";

}

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Second Largest Value

The program must accept a set of N integer values as command line arguments and print the second largest value. If there is no second largest value, print -1 as the output.

Example Input/Output 1:

Input:

20 30 30 20 30 15 12 11 10 6

Output:

20

Example Input/Output 2:

Input:

19 19 19 19 19 19

Output:

-1

Solution:

#include <stdio.h>

#include <stdlib.h>

void main(int c,char *a[])

{

    int i,f=-1,s,n;

    for(i=1;i<c;i++)

     {

         n=atoi(a[i]);

        if(n>f)

        {

            s=f;

            f=n;

        }

        else if(n>s&&n<f)

         s=n;

     }

     printf("%d",s);

}

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Only Alphabets and Space

Given a String S, remove all the special characters and numbers from S and print.

Input Format:

The first line contains the string S

Output Format:

The first line contains the string with only alphabets and spaces.

Boundary Conditions: 1 < Length of S < 1000

Example Input/Output 1:

Input:

Hello #$ World!

Output:

Hello World

Solution 1:

import re

print(''.join(re.findall('[A-Za-z]+|\s',input())))

Solution 2:

s=input()

for i in s:

    if i.isalpha() or i==' ':

       print(i,end='')

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Print Largest Even Number - Digits

Given a number N as the input, print the largest even number E that can be formed using the digits present in the number. (There will be at least one even digit).

Input Format:

The first line contains N.

Output Format:

The first line contains E.

Example Input/Output 1:

Input:

1902

Output:

9210

Solution:

n=list(input())

e=min(filter(lambda x:(ord(x)-ord('0'))%2==0,n))

n.remove(e)

n.sort(reverse=True)

n.append(e)

print(''.join(n))

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Reverse Number

The program must accept a number N using command line and prints the reverse of the number N.

Example Input/Output 1:

Input:

12345

Output:

54321

Example Input/Output 2:

Input:

10900

Output:

901

Solution:

#include <stdio.h>

#include <stdlib.h>

void main(int c,int *s[])

{

    int r=0,n=atoi(s[1]);

    while(n)

    {

        r=r*10+n%10;

        n/=10;

    }

    printf("%d",r);

}

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Integer - Sum of Digits

The program must accept an integer value N as a command line argument and print the sum of the digits in N.

Example Input/Output 1:

Input:

14

Output:

5

Example Input/Output 2:

Input:

1932

Output:

15

Solution:

#include <stdio.h>

#include <stdlib.h>

void main(int c,char *n[])

{

    int a=atoi(n[1]),s=0;

    while(a)

    {

        s+=a%10;

        a/=10;

    }

    printf("%d",s);

}

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